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-7x^2+15x=-25x-3x^2
We move all terms to the left:
-7x^2+15x-(-25x-3x^2)=0
We get rid of parentheses
-7x^2+3x^2+25x+15x=0
We add all the numbers together, and all the variables
-4x^2+40x=0
a = -4; b = 40; c = 0;
Δ = b2-4ac
Δ = 402-4·(-4)·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40}{2*-4}=\frac{-80}{-8} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40}{2*-4}=\frac{0}{-8} =0 $
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